UVA 511 Do You Know the Way to San Jose?

题目链接:https://vjudge.net/problem/UVA-511

题目翻译摘自《算法禁赛入门经典》

题目大意

  有 n 张地图(已知名称和两个对角线端点的坐标)和 m 个地名(已知名称和坐标), 还有 q 个查询。每张地图都是边平行于坐标轴的矩形,比例定义为高度除以宽度的值。每个查询包含一个地名和详细等级 i。面积相同的地图总是属于同一个详细等级。假定包含此地名的地图中一共有 k 种不同的面积,则合法的详细等级为 1~k(其中 1 最不详细,k 最详细, 面积越小越详细)。如果详细等级 i 的地图不止一张,则输出地图中心和查询地名最接近的一张;如果还有并列的,地图长宽比应尽量接近 0.75(这是Web浏览器的比例);如果还有并列,查询地名和地图右下角的坐标应最远(对应最少的滚动条移动);如果还有并列,则输出x坐标最小的一个。如果查询的地名不存在或者没有地图包含它,应报告查询非法。如果包含它的地图最高详细等级小于 i,应报告查询非法(并输出包含它的最详细地图名称,如果存在)。

分析

  对于每个询问,找出所有相关区域,然后用自定义比较器排一下序即可。

代码如下

  1 #include <bits/stdc++.h>
  2 using namespace std;
  3  
  4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
  5 #define Rep(i,n) for (int i = 0; i < (n); ++i)
  6 #define For(i,s,t) for (int i = (s); i <= (t); ++i)
  7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i)
  8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
  9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
 12  
 13 #define pr(x) cout << #x << " = " << x << "  "
 14 #define prln(x) cout << #x << " = " << x << endl
 15  
 16 #define LOWBIT(x) ((x)&(-x))
 17  
 18 #define ALL(x) x.begin(),x.end()
 19 #define INS(x) inserter(x,x.begin())
 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 
 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
 24  
 25 #define ms0(a) memset(a,0,sizeof(a))
 26 #define msI(a) memset(a,inf,sizeof(a))
 27 #define msM(a) memset(a,-1,sizeof(a))
 28 
 29 #define MP make_pair
 30 #define PB push_back
 31 #define ft first
 32 #define sd second
 33  
 34 template<typename T1, typename T2>
 35 istream &operator>>(istream &in, pair<T1, T2> &p) {
 36     in >> p.first >> p.second;
 37     return in;
 38 }
 39  
 40 template<typename T>
 41 istream &operator>>(istream &in, vector<T> &v) {
 42     for (auto &x: v)
 43         in >> x;
 44     return in;
 45 }
 46  
 47 template<typename T1, typename T2>
 48 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
 49     out << "[" << p.first << ", " << p.second << "]" << "\n";
 50     return out;
 51 }
 52 
 53 inline int gc(){
 54     static const int BUF = 1e7;
 55     static char buf[BUF], *bg = buf + BUF, *ed = bg;
 56     
 57     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
 58     return *bg++;
 59 } 
 60 
 61 inline int ri(){
 62     int x = 0, f = 1, c = gc();
 63     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
 64     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
 65     return x*f;
 66 }
 67 
 68 template<class T>
 69 inline string toString(T x) {
 70     ostringstream sout;
 71     sout << x;
 72     return sout.str();
 73 }
 74 
 75 inline int toInt(string s) {
 76     int v;
 77     istringstream sin(s);
 78     sin >> v;
 79     return v;
 80 }
 81 
 82 //min <= aim <= max
 83 template<typename T>
 84 inline bool BETWEEN(const T aim, const T min, const T max) {
 85     return min <= aim && aim <= max;
 86 }
 87  
 88 typedef long long LL;
 89 typedef unsigned long long uLL;
 90 typedef pair< double, double > PDD;
 91 typedef pair< int, int > PII;
 92 typedef pair< int, PII > PIPII;
 93 typedef pair< string, int > PSI;
 94 typedef pair< int, PSI > PIPSI;
 95 typedef set< int > SI;
 96 typedef set< PII > SPII;
 97 typedef vector< int > VI;
 98 typedef vector< double > VD;
 99 typedef vector< VI > VVI;
100 typedef vector< SI > VSI;
101 typedef vector< PII > VPII;
102 typedef map< int, int > MII;
103 typedef map< int, string > MIS;
104 typedef map< int, PII > MIPII;
105 typedef map< PII, int > MPIII;
106 typedef map< string, int > MSI;
107 typedef map< string, string > MSS;
108 typedef map< PII, string > MPIIS;
109 typedef map< PII, PII > MPIIPII;
110 typedef multimap< int, int > MMII;
111 typedef multimap< string, int > MMSI;
112 //typedef unordered_map< int, int > uMII;
113 typedef pair< LL, LL > PLL;
114 typedef vector< LL > VL;
115 typedef vector< VL > VVL;
116 typedef priority_queue< int > PQIMax;
117 typedef priority_queue< int, VI, greater< int > > PQIMin;
118 const double EPS = 1e-8;
119 const LL inf = 0x7fffffff;
120 const LL infLL = 0x7fffffffffffffffLL;
121 const LL mod = 1e9 + 7;
122 const int maxN = 1e4 + 7;
123 const LL ONE = 1;
124 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
125 const LL oddBits = 0x5555555555555555;
126 
127 int sgn(double x) {
128     if(fabs(x) < EPS) return 0;
129     return x > 0 ? 1 : -1;
130 }
131 
132 double dist(PDD a,PDD b) {
133   return sqrt((a.ft - b.ft) * (a.ft - b.ft) + (a.sd - b.sd) * (a.sd - b.sd));
134 }
135 
136 struct MAP{
137     double U, D, L, R, Area, ratio; // 上下左右和面积以及长宽比 
138     PDD center; // 中心点 
139     string name; 
140     
141     MAP() {}
142     MAP(string s) {
143         stringstream sin(s);
144         double x1, y1, x2, y2;
145         
146         sin >> name >> x1 >> y1 >> x2 >> y2;
147         L = min(x1, x2);
148         R = max(x1, x2);
149         U = max(y1, y2);
150         D = min(y1, y2);
151         center = MP((L + R) / 2, (U + D) / 2);
152         Area = (R - L) * (U - D);
153         ratio = fabs((R - L) / (U - D) - 0.75);
154     }
155     
156     bool cover(PDD x) {
157         return x.ft >= L && x.ft <= R && x.sd >= D && x.sd <= U;
158     }
159     
160     bool operator< (const MAP &x) const {
161         return Area > x.Area;
162     }
163 };
164 vector< MAP > maps;
165 
166 string tmp; 
167 map< string, PDD > loc;
168 string target;
169 int level;
170 
171 struct MyCmp{
172     bool operator() (const MAP &x, const MAP &y) const {
173         PDD tar = loc[target];
174         
175         if(sgn(x.Area - y.Area) == 0) {
176             double a = dist(tar, x.center);
177             double b = dist(tar, y.center);
178             
179             if(sgn(a - b) == 0) {
180                 if(sgn(x.ratio - y.ratio) == 0) {
181                     a = dist(tar, MP(x.R, x.D));
182                     b = dist(tar, MP(y.R, y.D));
183                     
184                     if(sgn(a - b) == 0) return x.L < y.L;
185                     return a > b;
186                 }
187                 return x.ratio < y.ratio;
188             }
189             return a < b;
190         }
191         return x.Area > y.Area;
192     }
193 }; 
194 
195 int main(){
196     //freopen("MyOutput.txt","w",stdout);
197     //freopen("input.txt","r",stdin);
198     //INIT();
199     getline(cin, tmp);
200     while(getline(cin, tmp)) {
201         if(tmp == "LOCATIONS") break;
202         maps.PB(MAP(tmp));
203     }
204     
205     while(getline(cin, tmp)) {
206         if(tmp == "REQUESTS") break;
207         stringstream sin(tmp);
208         double x, y;
209         
210         sin >> tmp >> x >> y;
211         loc[tmp] = MP(x, y);
212     }
213     
214     while(getline(cin, tmp)) {
215         if(tmp == "END") break;
216         stringstream sin(tmp);
217         
218         sin >> target >> level;
219         printf("%s at detail level %d ", target.c_str(), level);
220         
221         if(loc.find(target) == loc.end()) printf("unknown location\n");
222         else {
223             set< MAP, MyCmp > sm;
224             // 找出所有包含target地点的map
225             foreach(i, maps) if(i->cover(loc[target])) sm.insert(*i);
226                 
227             if(sm.size() == 0) printf("no map contains that location\n");
228             else {
229                 auto it = sm.begin();
230                 double t = 0;
231                 
232                 while(it != sm.end()) {
233                     if(it->Area != t) {
234                         t = it->Area;
235                         if(!--level) break;
236                     }
237                     ++it;
238                 }
239                 
240                 if(level) printf("no map at that detail level; using %s\n", sm.rbegin()->name.c_str());
241                 else printf("using %s\n", it->name.c_str());
242             }
243         }
244     }
245     return 0;
246 }
View Code

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转载自www.cnblogs.com/zaq19970105/p/11077277.html