[Swift]LeetCode1026. 节点与其祖先之间的最大差值 | Maximum Difference Between Node and Ancestor

Given the root of a binary tree, find the maximum value V for which there exists different nodes A and B where V = |A.val - B.val| and A is an ancestor of B.

(A node A is an ancestor of B if either: any child of A is equal to B, or any child of A is an ancestor of B.)

Example 1:

Input: [8,3,10,1,6,null,14,null,null,4,7,13]
Output: 7
Explanation: 
We have various ancestor-node differences, some of which are given below :
|8 - 3| = 5
|3 - 7| = 4
|8 - 1| = 7
|10 - 13| = 3
Among all possible differences, the maximum value of 7 is obtained by |8 - 1| = 7.

Note:

1. The number of nodes in the tree is between 2 and 5000.
2. Each node will have value between 0 and 100000.

---

给定二叉树的根节点 root，找出存在于不同节点 A 和 B 之间的最大值 V，其中 V = |A.val - B.val|，且 A 是 B 的祖先。

（如果 A 的任何子节点之一为 B，或者 A 的任何子节点是 B 的祖先，那么我们认为 A 是 B 的祖先）

示例：

输入：[8,3,10,1,6,null,14,null,null,4,7,13]
输出：7
解释： 
我们有大量的节点与其祖先的差值，其中一些如下：
|8 - 3| = 5
|3 - 7| = 4
|8 - 1| = 7
|10 - 13| = 3
在所有可能的差值中，最大值 7 由 |8 - 1| = 7 得出。

提示：

1. 树中的节点数在 2 到 5000 之间。
2. 每个节点的值介于 0 到 100000 之间。

---

Runtime: 416 ms

Memory Usage: 129.4 MB

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     public var val: Int
 5  *     public var left: TreeNode?
 6  *     public var right: TreeNode?
 7  *     public init(_ val: Int) {
 8  *         self.val = val
 9  *         self.left = nil
10  *         self.right = nil
11  *     }
12  * }
13  */
14 class Solution {
15     func maxAncestorDiff(_ root: TreeNode?) -> Int {
16         var list:[[Int]] = binaryTreePaths(root)
17         var res:Int = 0
18         for arr in list
19         {
20             res = max(res,getMaxDifference(arr))
21         }
22         return res
23     }
24     
25     func getMaxDifference(_ arr:[Int]) -> Int
26     {
27         var res:Int = 0
28         for i in 0..<arr.count
29         {
30             for j in (i + 1)..<arr.count
31             {
32                 res = max(res,abs(arr[i] - arr[j]))
33             }
34         }
35         return res
36     }
37     
38     //获取所有子树
39     func binaryTreePaths(_ root: TreeNode?) -> [[Int]] {
40         var list:[[Int]] = [[Int]]()
41         recuesive(root,&list,[Int]())
42         return list
43     }
44     
45     func recuesive(_ root:TreeNode?,_ list:inout [[Int]],_ arr:[Int])
46     {
47         if root == nil {return}
48         var arrNew:[Int] = arr
49         var arrRoot:[Int] = [root!.val]
50         if root?.left == nil && root?.right == nil
51         {
52             arrNew += arrRoot
53             list.append(arrNew)
54             return
55         }
56         arrRoot = arrNew + arrRoot
57         recuesive(root?.left,&list,arrRoot)
58         recuesive(root?.right,&list,arrRoot)
59     }
60 }