SqlServer如何判断字段中是否含有汉字?

--/* 
--unicode编码范围: 
--汉字:[0x4e00,0x9fa5](或十进制[19968,40869]) 
--数字:[0x30,0x39](或十进制[48, 57]) 
--小写字母:[0x61,0x7a](或十进制[97, 122]) 
--大写字母:[0x41,0x5a](或十进制[65, 90]) 
--根据编码范围来判断 
--*/
--创建
 
create proc p_A_VIC 
as 
declare @count int 
declare @i int 
declare @text nvarchar(50) 
set @i = 0
set @count = (select COUNT (*) from table  )
while(@i < @count )
begin
    set @i +=1
    --sid代表有一定循环规律的,若是无序的可以添加一个序列(Row_Number() OVER ---)。
    --select * from (SELECT *, Row_Number() OVER ( ORDER BY [sid] ) num FROM s--table ) as s where num = 3
    set @text = (select  a from table  where [sid] = @i)
    if unicode(@text) between 19968 And 40869 or unicode(@text) between 97 And 122 or unicode('a') between 65 And 90
    begin
      print 0
    end
    else
       print @text
end
--执行 
exec  p_A_VIC

实例1:

---由于某些原因HouseName 字段存入了GUID,为了区分
SELECT HouseName FROM ZSGYTD_HouseInfo 
SELECT HouseName FROM ZSGYTD_HouseInfo WHERE UNICODE(HouseName) BETWEEN 19968 AND 40869

执行结果:

实例2:

----将上述存入ZSGYTD_Estate 表ID的houseName进行左连接,获取到对应的Name
SELECT h.HouseName,
CASE WHEN UNICODE(h.HouseName) BETWEEN 19968 AND 40869 then h.HouseName 
     ELSE e.Name
     END housename2    
FROM ZSGYTD_HouseInfo  h
LEFT JOIN ZSGYTD_Estate e ON CONVERT(varchar(50),e.ID)=h.HouseName and e.IsDeleted=0 


select*from ZSGYTD_Estate

执行结果:

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转载自www.cnblogs.com/dyhao/p/10072094.html
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