从扑克中每次取出4张牌。使用加减乘除，第一个能得出24者为赢。（其中，J代表11，Q代表12，K代表13，A代表1），按照要求编程解决24点游戏。 基本要求： 随机生成4个代表扑克牌牌面的数字字母，

#coding=UTF-8

import tkinter as tk
from random import randint
from itertools import permutations

#4个数字和2个运算符可能组成的表达式形式
exps = ('((%s %s %s) %s %s) %s %s',
        '(%s %s %s) %s (%s %s %s)',
        '(%s %s (%s %s %s)) %s %s',
        '%s %s ((%s %s %s) %s %s)',
        '%s %s (%s %s (%s %s %s))')
ops = r'+-*/'

window = tk.Tk()
window.title('24 Game')
window.geometry('620x600')


def test24(v):
    result = []
    #Python允许函数的嵌套定义
    #这个函数对字符串表达式求值并验证是否等于24
    def check(exp):
        try:
            #有可能会出现除0异常，所以放到异常处理结构中
            return int(eval(exp)) == 24
        except:
            return False
    #全排列，枚举4个数的所有可能顺序
    for a in permutations(v):
        #查找4个数的当前排列能实现24的表达式
        t = [exp % (a[0], op1, a[1], op2, a[2], op3, a[3]) for op1 in ops for op2 in ops for op3 in ops for exp in exps if check(exp %(a[0], op1, a[1], op2, a[2], op3, a[3]))]
        if t:
            result.append(t)
    return result

def clr():
    e1.delete('0', 'end')
    e2.delete('0', 'end')
    e3.delete('0', 'end')
    e4.delete('0', 'end')
    t.delete(1.0, tk.END)
    
def Cal_clr():
    t.delete(1.0, tk.END)

def Cal():
    Cal_clr()
    lst=[]
    a1=int(e1.get())
    a2=int(e2.get())
    a3=int(e3.get())
    a4=int(e4.get())
    lst.append(a1)
    lst.append(a2)
    lst.append(a3)
    lst.append(a4)
#     print(lst)
    r = test24(lst)
    cnt=0
    if r:
        for i in range(len(r)):
            print(r[i])
            for j in range(len(r[i])):
                print(r[i][j])
                t.insert('insert', r[i][j]+'   ')
                cnt+=1
                if(cnt==4):
                    cnt=0
                    t.insert('insert', '\n')
    else:
        print('No answer for ', lst)
        t.insert('insert', 'No answer for ')
        t.insert('insert', lst)


    
# 标签
w = tk.Canvas(window, width=620, height=600)
w.pack()
w.create_rectangle(470, 0, 470+150, 0+55, fill='skyblue')
l_title = tk.Label(window, text=' 24 点', bg='skyblue', font='黑体 -30', fg='red')
l_title.place(x=490, y=10)

# 提示语句
var = tk.StringVar()
l = tk.Label(window, text="请输入四个数字：", font=('NewTimesRoman', 16), 
             width=15, height=2)
l.place(x=100, y=50, anchor='center')

# 四个输入
e1=tk.Entry(window, show='', font = 'NewTimesRoman -20 bold', width=5) 
e1.place(x=80, y=100, anchor='center')
e2=tk.Entry(window, show='', font = 'NewTimesRoman -20 bold', width=5) 
e2.place(x=200, y=100, anchor='center')
e3=tk.Entry(window, show='', font = 'NewTimesRoman -20 bold', width=5) 
e3.place(x=320, y=100, anchor='center')
e4=tk.Entry(window, show='', font = 'NewTimesRoman -20 bold', width=5) 
e4.place(x=440, y=100, anchor='center')

# 结果输出提示
l = tk.Label(window, text="24点运算结果为：", font=('NewTimesRoman', 16), 
             width=15, height=2)
l.place(x=100, y=200, anchor='center')

# 结果显示
t = tk.Text(window, width=160, height=50, font=('NewTimesRoman', 11))
t.place(y=240, anchor='nw')

# 计算按钮
b = tk.Button(window, text='计算', command=Cal, width=8)
b.place(x=200, y=150, anchor='center')

# 清空按钮
b_clr = tk.Button(window, text='清空', width=8, command=clr)
b_clr.place(x=320, y=150, anchor='center')

window.mainloop()