输入包含多组数据,每组数据占一行,格式为"a + b ="
相邻的两个字符串之间有一个空格隔开。当a,b同时为0的时候退出
Output
每次输入占一行,输入整数表示下的a+b
Sample Input
one + two = three four + five six = zero + zero =
Sample Output
3 90
先从每个空格分离成几个字符串,把字符串对应成相应数字,开标记确定加号位置。
#include <stdio.h>
#include <stdlib.h>
#include<string.h>
int main()
{
int i=0,n,j,k=0,m,rnum[4]= {0},l,flag[4]= {0},sum1=0,sum2=0;
char str[5][10]= {"0"},a[100]= {0};
char number[10][10]= {"zero","one","two","three","four","five","six","seven","eight","nine"};
while(1)
{
for(i=0; i<5; i++)
{
for(j=0; j<10; j++)
str[i][j]=0;
}
for(i=0; i<100; i++)
a[i]=0;
for(i=0; i<4; i++)
{
flag[i]=0;
rnum[i]=0;
}
gets(a);
i=l=0,k=0,sum1=sum2=0;
n=strlen(a);
for(j=0; j<n; j++)
{
if(a[j]==32)
{
i++;
k=0;
continue;
}
else
{
str[i][k]=a[j];
k++;
}
}
for(m=0; m<=i; m++)
{
if(strcmp(str[m],"+")==0)
flag[m]=1;
for(j=0; j<10; j++)
if(strcmp(str[m],number[j])==0)
{
rnum[l]=j;
l++;
}
}
for(m=0; flag[m]!=1; m++)
sum1=sum1*10+rnum[m];
for(; m<l; m++)
sum2=sum2*10+rnum[m];
if(sum1==0&&sum2==0)
break;
printf("%d\n",sum1+sum2);
}
return 0;
}