有若干只兔和鸡,兔和鸡加起来一共有100条腿,请写一个简单的shell脚本,列出兔和鸡各有多少只的所有组合(假设所有的兔和鸡的腿都是健全的,且兔和鸡至少为1只)...

#!/bin/bash for rabbits in $(seq 1 100); do chickens=$((100 - $rabbits)) echo "rabbits: $rabbits, chickens: $chickens" done

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转载自blog.csdn.net/weixin_35756373/article/details/129515633