[PAT B] Practise 1016 Part A + B

PAT (Basic Level) Practice (Chinese) 1016

1016 Part A + B

Positive integer A of "D * A ** (as an integer) portion" is defined as A * all * D ** A * new compositions integer P A . For example: Given A = 3862767, D A = 6, then A "section 6" of the * P ** A * 66, because A has two 6.

Now given A , D A , B , D B , write a program to calculate P A + P B .

Input formats:

In the given input line are sequentially A , D A , B , D B , separated by a space, where 0 < A , B <1010.

Output formats:

Output line P A + P B value.

Sample Input 1:

3862767 6 13530293 3

Output Sample 1:

399

Sample Input 2:

3862767 1 13530293 8

Output Sample 2:

0

Ideas:

Digital calculation is repeated string meaning of the questions and the new string can be configured according Da Db.

Code:

#include <iostream>
#include <string>
using namespace std;
int inWath(string s,char k) {
    int n = 0;
    for (int i = 0; i < s.size(); i++) {
        if (s[i] == k)
            n++;
    }
    return n;
}
int main() {
    string a, b;
    char   Da,Db;
    string Pa,Pb;
    cin >> a >> Da >> b >> Db;
    if (inWath(a, Da) != 0 && inWath(b, Db) != 0)
        cout << stoi(Pa.insert(0, inWath(a, Da), Da)) + stoi(Pb.insert(0, inWath(b, Db), Db));
    else
        cout << "0";
    return 0;
}