Subject description:
Given interval [-2 31 is 2 31 is ] an integer of 3 A, B and C in, please determines whether A + B is greater than C.
Input formats:
The first input line is given positive integer T (≤10), are the number of test cases. T is then given set of test cases, each per line, the order is given A, B and C. Between integer separated by a space.
Output formats:
For each test case, the output in line Case #X: true if A + B> C, otherwise the output Case #X: false, where X is the test case number (starting from 1).
Sample input:
4
1 2 3
2 3 4
2147483647 0 2147483646
0 -2147483648 -2147483647
Sample output:
Case #1: false
Case #2: true
Case #3: true
Case #4: false
Problem-solving ideas:
Note range
Code:
#include<iostream>
using namespace std;
int main() {
int num =0;
long long A,B,C;
cin >> num;
for (int i=0;i< num;i++) {
cin >> A>>B>>C;
if (A+B > C) {
cout << "Case #" <<i+1<< ":" << " true"<< endl;
}
else {
cout << "Case #" <<i+1<< ":" << " false"<< endl;
}
}
return 0;
}