Find the maximum and minimum values of the float array, respectively, and the first and last elements interchange

 1 #include<stdio.h>
 2 float a[10];
 3 float *p;
 4 int main()
 5 {
 6     void input(float*,int);
 7     void output(float*,int);
 8     void change(float*,int);
 9     p=a;
10     input(p,10);
11     printf("输入完成\n");
12 is      Change (P, 10 );
 13 is      the printf ( " operation completed \ n- " );
 14      Output (P, 10 );
 15      the printf ( " output completion \ n- " );
 16      return  0 ;
 . 17  }
 18 is  
. 19  int min ( a float A *, int n-)
 20 is  {
 21 is      int min = 0 ;
 22 is      for ( int I = . 1 ; I <n-; I ++ )
 23 is      {
24         if(*(a+min)>*(a+i)) min=i;
25     }
26     return min;
27 }
28 int max(float *a,int n)
29 {
30     int max=0;
31     for(int i=1;i<n;i++)
32     {
33         if(*(a+max)<*(a+i)) max=i;
34     }
35     return max;
36 }
37 
38 void input(float*a,int n)
39 {
40     for(int i=0;i<n;i++)
41     {
42         scanf("%f",a+i);
43     }
44 }
45 
46 void change(float *a,int n)
47 {
48     int i=min(a,n);
49     int j=max(a,n);
50     if(j==0) j=i;      //Carefully understand an importance 
51 is      a float TEMP = * (A + I);
 52 is      * (A + I) = * A;
 53 is      * A = TEMP;
 54 is      
55      TEMP = * (A + J);
 56 is      * (A + J ) = * (A + N- . 1 );
 57 is      * (A + N- . 1 ) = TEMP;
 58  }
 59  
60  void Output ( a float * A, int n-)
 61 is  {
 62 is      for ( int I = 0 ; I <n- ; i ++) printf ( " % 7.2f " , * A ++ );
 63     printf("\n");
64 }

operation result: