JS Basics--Find the maximum and minimum values of an array

If there is a requirement:

Find the maximum and minimum values ​​in the array let arr = [72, 6, 13, 7, 400, 55, 88, 100, 800]

analyze:

①: Declare a variable max that holds the largest element.

②: The default maximum value can be the first element in the array.

③: Traverse the array and compare each array element with max.

④: If the array element is greater than max, store the array element in max, otherwise continue to the next round of comparison.

⑤: Finally output this max.

The minimum value is the same

code:

    let arr = [72, 6, 13, 7, 400, 55, 88, 100, 800]
    // max里面要存的是最大值，初始值为数组的第一个元素
    let max = arr[0]
    // min 要存放的是最小值，初始值为数组的第一个元素
    let min = arr[0]
    // 遍历数组
    for (let i = 1; i < arr.length; i++) {
      // 如果max 比 数组元素里面的值小，我们就需要把这元素赋值给 max
      // if (max < arr[i]) max = arr[i]
      max < arr[i] ? max = arr[i] : max
      // 如果min 比 数组元素大， 我们就需要把数组元素给min
      min > arr[i] ? min = arr[i] : min
    }
    // 输出 max,min
    console.log(`最大值是: ${max}`)  // 最大值是: 800
    console.log(`最小值是: ${min}`)  // 最小值是: 6