Find the maximum and minimum array

Three ways to find the maximum and minimum values ​​in the array

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public  class ArrayAlg { 

    public  static  void main (String [] args) {
         // find the maximum value of the array 
        Double [] = Doubles 22.1,32.5,56.2,45.2,78.2 { };
         / * Method a: Arrays.sort (doubles ); 
        System.out.println (of Arrays.toString (Doubles)); 
        System.out.println ( "maximum value is:" + Doubles [-doubles.length. 1]); 
        System.out.println ( "minimum of: "Doubles + [0]); 
         * / 

        / * method two: Double Doubles = max [0]; 
        for (int I = 0; I <-doubles.length. 1; I ++) { 
           IF (max <Doubles [I +. 1 ]) { 
               max = Doubles [I +. 1]; 
           }  
        }
        System.out.println ( "maximum value is:" + max);

        double min=doubles[0];
        for (int i=0;i<doubles.length-1;i++){
            if (min>doubles[i+1]){
                min=doubles[i+1];
            }
        }
        System.out.println("最小值为:"+min);
        */

        /*方法三：double min=Double.POSITIVE_INFINITY;
        double max=Double.NEGATIVE_INFINITY;
        for (double d:doubles){
            if (min>d){
                min=d;
            }
            if (max<d){
                max=d;
            }
        }
        System.out.println("最大值为:"+max+"最小值"+min);
         */
    }


}