constxiong.interview Package;
Import java.util.regex.Matcher;
Import java.util.regex.Pattern;
/ * *
* count the number of occurrences of a string of a long string
* @author ConstXiong
* @date 2019-11- 11:01:22 13 is
* /
public class TestCountWordTimesInText {
public static void main (string [] args) {
string text = " statistical segment length CX CX a string of a string C is now the number of times X CX " ;
string Word = " the CX " ;
the System. OUT .println (countWordTimesByCutString (text, Word));
. the System OUT.println (countWordTimesByReplace (text, Word));
the System. OUT .println (countWordTimesByRegex (text, Word)); // regular match, wildcard required injection affect the results
}
/ * *
* Statistics taken String String occurrence
* @param text
* @param Word
* @return
* /
public static int countWordTimesByCutString (text String, String Word) {
int times = 0 ;
IF (!! isEmpty (text) && isEmpty (Word)) {
String SubText = text;
int index = - . 1 ;
int wordlength = word.length ();
the while (subText.length ()> wordlength = && (index = subText.indexOf (Word))> - . 1 ) {
SubText = subText.substring (index + wordlength);
Times ++ ;
}
}
return times;
}
/ * *
* by substituting a string, the string count occurrences
* @param text
* @param Word
* @return
* /
public static int countWordTimesByReplace (text string, string Word) {
int times = 0;
IF (!! IsEmpty (text) && isEmpty (Word)) {
Times = (text.length () - text.replace (Word, "" ) .length ()) / word.length ();
}
return Times;
}
/ * *
* number of occurrences of regular expressions, statistical string
* @param text
* @param Word
* @return
* /
public static int countWordTimesByRegex (text string, string Word) {
int times = 0 ;
IF (isEmpty (! text) &&! isEmpty (Word)) {
the Pattern P = Pattern.compile(word);
Matcher m = p.matcher(text);
while (m.find()) {
times++;
}
}
return times;
}
/**
* 字符串是否为空
* @param str
* @return
*/
private static boolean isEmpty(String str) {
return str == null || str.length() == 0;
}
}
