Determine the number of occurrences of each number in the number string

Given a string composed of numbers such as: "1239586838923173478943890234092"; count the number of times each number appears.

Use String common classes and for loop

	String str = "1239586838923173478943890234092";
	//将字符串转化为字符数组
	char[] ch = str.toCharArray();
	//外层循环将字符0-9与目标字符串比较
	//字符'0'在字符集中是48代替,且字符可以加加操作和比较操作
	for(int i = '0' ; i < '9' ; i++){
    
    
		//记录相同数字的个数(每次循环需要置为0)
	    int count = 0;
		//内层循环一次将i和字符串从头到尾比较一次
		for(int j = 0; j < ch.length; j++){
    
    
			if(ch[j] == i){
    
    
				coun++;t
			}
		}
		//内层循环结束后打印
		System.out.println("数字"+ i +"出现的次数" + count);	
	}

Output result:

0 appeared 2 times
1 appeared 2 times
2 appeared 4 times
3 appeared 6 times
4 appeared 3 times
5 appeared 1 time
6 appeared 1 time
7 appeared 2 times
8 appeared 5 times

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Origin blog.csdn.net/weixin_44906436/article/details/108598063