Recursive descent parser (parsing)

 

1. grammar  G ( S ) :

1S -> AB

2A ->Da|ε

3B -> cC

4C -> aADC |ε

5D -> b|ε

Verify grammar  G ( S ) is not  LL ( . 1 ) grammar?

 

FIRST

FIRST(Da)={b,a}

FIRST (e) = {e}

FIRST(cC)={c}

FIRST(aADC)={a}

FIRST(b)={b}

 

FOLLOW

FOLLOW(A)={c,b,a,#}

其中#FOLLOW(A)=FOLLOW(C)=FOLLOW(B)=FOLLOW(S)

FOLLOW(B)={#}

FOLLOW(C)={#}

FOLLOW(D={a,#}

 

SELECT Set

SELECT(A->Da)=FIRST(Da)={b,a}

SELECT(A->ε)=FOLLOW(A)={c,b,a,#}

SELECT(C->aADC)=FIRST(aADC)={a}

SELECT(C->ε)=FOLLOW(C)={#}

SELECT(D->b)=FIRST(b)={b}

SELECT(D->ε)=FOLLOW(D)={a,#}

 

Since the SELECT (A-> Da) the SELECT ( A-> [epsilon] ) ≠ ∅

SElECT(C->aADC)∩SELECT(C->ε)=

SELECT(D->b)SELECT(D->ε)=

Therefore, G (S) is not LL (1) syntax.

 

 

 

 

 

 

 

 

 

 

2. ( last job ) to eliminate left after the recursive expression grammar whether it is LL (1) grammar?

Eliminate left recursion too:

E-> TE '

E '-> + TE' | e

T->FT’

T’->*FT’|ε

F->(E)|i

 

FIRST集:

FIRST(TE’)={ (, i }

FIRST (TE + ') = {+ , e}

FIRST(FT’)={(,i}

FIRST(*FT')={ *,ε}

FIRST((E))={ (}

FIRST(i)={ i }

 

FOLLOW集:

FOLLOW(E)={ ),# }

FOLLOW(E')={ ),# }

FOLLOW(T)={+,),#}

FOLLOW(T')={+,),#}

FOLLOW(F)={*,+,),#}

 

SELECT set:

SELECT (E -> TE’) = FIRST(TE’) = { ( , i }

SELECT(E’ -> +TE’) = FIRST(+TE’) = { + }

SELECT(E’ -> ε) = FIRST(ε) - {ε} U FOLLOW(E’) = FOLLOW(E’) = { ) , # }

SELECT(T -> FT’) = FIRST(FT’) = { ( , i }

SELECT(T’ -> *FT’) = FIRST(*FT’) = { * }

SELECT(T’ -> ε) = FIRST(ε) - {ε} U FOLLOW(T’) = FOLLOW(T’) = { + , ) ,# }

SELECT(F -> (E)) = FIRST((E)) = { ( }

SELECT(F -> i) = FIRST(i) = { i }

 

SELECT(E’ -> +TE’) = FIRST(+TE’) = { + } ∩ SELECT(E’ -> ε) = FOLLOW(E’) = { ) , # }=

SELECT(T’ -> *FT’) = FIRST(*FT’) = { * } ∩ SELECT(T’ -> ε) =FOLLOW(T’) = { + , ) ,# }=

SELECT(F -> (E)) = FIRST((E)) = { ( } SELECT(F -> i) = FIRST(i) = { i }=

Therefore, the grammar is LL (1) syntax.

 

 

 

 

 

 

 

3. The connection 2 , if it is LL (1) grammar, write its recursive descent parser code.

E()

    T();

       E'();

     }

E'()

T()

T'()

F()

 

Void ParseE()

{       

         Switch(lookahead){

         case ’(‘,’I’:

                  Frset ();

                  ParseE’()

break;

default:

printf("syntx error\n");

    exit(0);

}

}

 

Void ParseE’()

{

         Switch(lookahead){

                  case ‘+’:

                            Match Token (+);

                            Frset ();

                            ParseE’();

                            break;

       case ‘)’,’#’

                            break;

default:

printf("syntx error\n");

                 exit(0);

 

}

}

 

Void ParseT()

{       

         Switch(lookahead){

         case ‘(’,’i’

                  ParseF();

                  Frset '();

                  break;

default:

printf("syntx error\n");

        exit(0);

 

}

 

}

Void ParseT’()

{       

         Switch(lookahead){

          case  ‘*’:

                   Match Token (*);

                   ParseF();

                   Frset '();

                   break;

         case  ‘+’ ,’ )’ ,’#’:

                   break;

default:

printf("syntx error\n");

        exit(0);

 

}

}

void ParseF(){

  switch(lookahead){

        case '(':

                Match Token ( '(');

                ParseE();

                Match Token ( ')');

                break;

        case 'i':

               Match Token ( 'in');

               break;

        default:

              printf("syntx error\n");

                exit(0);

    }

}

 

 

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Origin www.cnblogs.com/zhff/p/11897801.html