Experiment 3 loop

Part1:

 

Part2:

#include <stdio.h> 
#include <stdlib.h> 
int main () { 
	int Number, max, min, n-; 
    
	n-=. 1; 
	the printf ( "Enter the number of D%:", n-); 
	Scanf ( " % D ", & number); 
	max = number; 
	min = number; 
    
	the while (n-<. 5) { 
		n-++; 
		the printf (" enter number of% D: ", n-); 
		Scanf ("% D ", & number);	 

        IF (max <= number) 
			max = number; 
		the else IF (min> = number) 
			min = number; 
	} 
    
	the printf ( "maximum number:% d \ n", max); 
	the printf ( "minimum number:% d \ n ", min); 
	
	System (" PAUSE "); 
	
	return 0; 
}

　　

part3

#include <stdio.h>
int main(){
    int n=0;  
    int x=101;
    int a=2;
    for(;x<=200;a=2){
        while(x%a)
        {
            if(a<x)
            {a++;}        
        }
        if(a==x)
        {
            n++;
            if(n%5!=0)
            {printf("%6d",x);}
            else
            {printf("%6d\n",x);}
}
        x++;
    }
    printf("\n");
    printf("101~200之间共有%d个素数。",n); 
    return 0;
}

　　

#include <stdio.h>
#include <math.h>
int main(){
    int number;
    int n=0;
    int a,b;
    int result=0;
    printf("Enter a number：");
    scanf("%d",&number);
    while(number){
        a=number%10;
        number=number/10;
        if(a%2){
            n++;
            result=result+a*pow(10,n-1);
        }        
    }
    printf("new number is:%d",result);
    return 0;
} 

　　

 

 

#include<stdio.h>
int main()
{
	double n,a,j;
	double s=0,m=1;
	printf("Enter n and a:");
	scanf("%lf%lf",&n,&a);
	for(j=1.0000;j<=n;j++)
	{   s=(j/m)+s;
		m=m*10+1;
	}
	printf("s=%.6lf",s/a);
	return 0;
	}