Track TABLE DROP; DROP TABLE Album; the CREATE TABLE Album ( albumCode VARCHAR (10) the NOT NULL PRIMARY KEY - album number , title VARCHAR (50) - album title , artist VARCHAR (50) - author , price DECIMAL (10, 2) - price , rdate DATETIME - release date , label VARCHAR (50) - record companies , rank INTEGER - album rankings ) the DEFAULT CHARSET = utf8; the CREATE TABLE Track ( album VARCHAR (10) the NOT NULL - album No , dsk INTEGER NOT NULL - the disc number , posn INTEGER NOT NULL - song disc position , song VARCHAR (255) - the name of the song , PRIMARY KEY (Album, DSK, posn) , a FOREIGN KEY (Album) the REFERENCES Album (albumCode) ) the DEFAULT the CHARSET = UTF8; the SELECT * the FROM Album; the SELECT * Track the FROM; - Find the album title (name) and artist (author) contains song (song) 'Alison' the SELECT a.title, a.artist FROM album a, track t WHERE a.albumCode = t.album AND t.song = 'Alison' - which artist (author) recorded the song (the song) 'Exodus' the SELECT Artist Album the FROM a, the WHERE a.albumCode track t = t.album the AND t.song = 'Exodus' - lists the track (tracks table) all belong to 'Blur' album (album) in the song (song) the SELECT Track song the FROM T, the WHERE a album title = 'Blur' = t.album the AND a.albumCode - displays each album (album) in the title (name) and the track number of the track comprising the SELECT a.title, COUNT (Song) the FROM track T, the WHERE a.albumCode album a = t.album the GROUP BY a.title - displays each album (album) in the title (name) and track names contained in the 'Heart' the total number of tracks SELECT a.title, COUNT (t.song) FROM album a LEFT JOIN track t ON a.albumCode = t.album WHERE t.song LIKE '% Heart' GROUP BY a .album code - find all the song (the song) and title (album name) the same track the SELECT t.song the FROM t Track, Album A = t.album the WHERE a.albumCode the AND a.title = t.song - find all the album name (title) and artist (author) same album the SELECT a.title the FROM t Track, album a = a.artist the WHERE a.title - find appear in two more songs off the album, contains both appear the number of the SELECT t.song, COUNT (a, albumCode) Track C the FROM T = the JOIN Album a t.album the ON a.albumCode the GROUP BY t.song the HAVING C> 2 - find the price per song is less than 0.5 The album, display album title, price, and total number of tracks the SELECT a.title, a.price, COUNT (t.song) c t the FROM track, album A = t.album the WHERE a.albumCode the GROUP BY t.song the HAVING a.price / C <0.5 - how many tracks by album contains from more to less lists album name (title), and comprising a total number of tracks SELECT title, COUNT (t.song) c fROM track t, album a WHERE a.albumCode = t.album BY a.albumCode the GROUP the ORDER BY DESC c