I think we are the product of two vectors for a number of awareness is already very clear, so they do not repeat them. Directly from the vector product of two vectors to begin with.
\ [a \ times b \]
two vectors as a vector multiplication product, will be a vector perpendicular to the plane of these two vectors, the direction back because \ (a \ times b \) in \ (a, b \) swapping changes (anti-vector product exchange, the exchange will make changes sign), and perhaps to a predetermined specific operation of a coordinate system related to the right hand position.
The formula is,
\ [| A \ Times B | = | A || B | \ SiN \ angle (A, B) \]
That is equal to the length of the vector quantity vector obtained as the vector product of the number (modulo) in the two vectors limb area of a parallelogram. (This is of course in the case of non-collinear)
necessary and sufficient conditions for two collinear vectors is the vector product is zero
Which meet on the number of factors binding rate
\ [\ lambda (a \ times
b) = (\ lambda a) \ times b = a \ times (\ lambda b) \] from and can be drawn:
\ [(\ the lambda a) \ times (\ mu b ) = (\ lambda \ mu) (a \ times b) \]
Vector product also satisfies the distribution ratio, i.e.:
\ [(A + B) \ C Times = A \ B + C Times \ C Times \]
and can be derived from:
\ [A \ Times (B + C) = A \ times b + a \ times c
\] of course, in this section the most important are the following equation:
If \ (a = X_1 I + Y_1 J + Z_1 K \) , \ (B = X_2 I + Y_2 J + Z_2 K \)
then
\ [a \ times b = \
begin {vmatrix} i & j & k \\ X_1 & Y_1 & Z_1 \\ X_2 & Y_2 & Z_2 \ end {vmatrix} \] this is an important formula