Synchronization: buringstraw.win/archives/59/
N0lP 2018 monetary system
Paddle week wrote this stuff?
topic
Currency species \ (n-\) , the denomination of the array \ (a [1..n] \) of the money system referred to as \ ((n-, A) \) .
Two money system $ (n, a) $ and $ (m, B) \ (are equivalent if and only if for any non-negative integer \) X $, it can be either system are Expressed two currencies or any one of them can not be Expressed.
Find a currency \ ((m, b) \ ) , satisfies \ ((m, b) \ ) with the original currency \ ((n, a) \ ) equivalent, and \ (m \) possible small.
The minimum output \ (m \)
solution
If a monetary system where money can be certain other currencies, then you can kick off.
Therefore, the first sort, then each a[i]
can be expressed, it is marked,
Reuse thought to backpack full screen (to be full of money mark)
Code
#include <cstdio>
#include <algorithm>
using std::max;
using std::sort;
const int MAXN = 105, MAXA = 25000;
int main (void) {
int T;
scanf("%d", &T);
while (T--) {
int a[MAXN] = {0};
bool v[MAXA] = {0};
int n, maxa = 0, ans = 0;
scanf("%d", &n);
for (int i = 1; i <= n; ++i) {
scanf("%d", a + i);
maxa = max(maxa, a[i]);
}
sort(a + 1, a + 1 + n);
for (int i = 1; i <= n; ++i) {
if (v[a[i]]) continue;
++ans;
v[a[i]] = 1;
for (int j = a[i]; j <= maxa; ++j) {
if (v[j - a[i]]) v[j] = 1;
}
}
printf("%d\n", ans);
}
return 0;
}