Hand dong dong brain

 1 yuan fan code code code bu

 

Achieve certification program

package complement;

import java.util.Scanner;

public class complement
{
    public static void main(String[] args)
    {
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入一个(-127)-128的整数a");
        int Originala;
        int Originalb;
        while (true)
        {
            Originala = sc.nextInt();
            if (Originala >= -127 && Originala <= 128)
            {
                System.out.println ( "A is the original code:" + GetBinary (Originala));
                 IF (Originala> 0 ) 
                { 
                    System.out.println ( "A code counter is:" + GetBinary (Originala)); 
                    the System .out.println ( "a's complement is:" + GetBinary (Originala)); 
                } the else 
                { 
                    System.out.println ( "a code counter is:" + getReverse (GetBinary (Originala))); 
                    the System.out .println ( "a's complement is:" + getComplement (getReverse (GetBinary (Originala)))); 
                } 

                BREAK ;
            } The else 
            { 
                System.out.println ( "out of range, please re-enter" ); 
            } 
        } 
        System.out.println ( "Enter a (-127) -128 integers A" );
         the while ( to true ) 
        { 
            Originalb = sc.nextInt ();
             IF (Originalb> = -127 && Originalb <= 128 ) 
            { 
                System.out.println ( "B is the original code:" + GetBinary (Originalb));
                 IF (Originalb> 0 ) 
                {
                    System.out.println ( "Code B counter is:" + GetBinary (Originalb)); 
                    System.out.println ( "B's complement is:" + GetBinary (Originalb)); 
                } the else 
                { 
                    System.out.println ( "inverse code B is:" + getReverse (GetBinary (Originalb))); 
                    System.out.println ( "B's complement is:" + getComplement (getReverse (GetBinary (Originalb)))); 
                } 

                BREAK ; 
            } the else 
            { 
                System.out.println ( "out of range, please re-enter" ); 
            } 
        }
        String ca=getComplement(getReverse(getBinary(Originala)));
        String cb=getComplement(getReverse(getBinary(Originalb)));
       int [] complementa=new int[8];
       int [] complementb=new int[8];
       for(int i=0;i<8;i++) {
           complementa[i]=Integer.parseInt(ca.charAt(i)+"");
           complementb[i]=Integer.parseInt(cb.charAt(i)+"");
       }
       System.out.println("按位与的结果：");
       System.out.println(getBinary(Originala&Originalb));
       System.out.println("按位异或的结果：");
       System.out.println(getBinary(Originala^Originalb));

    }
    
    
    public static String getBinary(int k)
    {
        String str = "";
        if (k == 0)
            return "00000000";
        else
        {
            int flag = k > 0 ? 1 : 0;
            k = k > 0 ? k : (-k);
            while (k != 0)
            {
                str = k % 2 + str;
                k = k / 2;
            }
            int in = Integer.parseInt(str);
            if (flag == 1)
            {
                str = String.format("%08d", in);
            } else
            {
                str = "1" + String.format("%07d", in);
            }

            return str;
        }
    }

    public static String getReverse(String str)
    {
        String str2 = "";
        for (int i = 1; i < str.length(); i++)
        {
            if (str.charAt(i) == '1')
            {
                str2 = str2 + "0";
            } else if (str.charAt(i) == '0')
            {
                str2 = str2 + "1";
            }
        }
        return "1" + str2;
    }

    public static String getComplement(String str)
    {
        if ("11111111".equals(str))
            return "00000000" ;
         the else 
        { 
            int index = 0 ; 
            String str2 = "" ;
             int In Flag = (the Integer.parseInt (str.charAt (. 7) + "") +. 1) == 2. 1: 0;? // . 1 represents binary 0 indicates no carry 
            IF (in Flag ==. 1 ) 
            { 
                for ( int I = str.length () -. 1; I> = 0; i-- ) 
                { 
                    IF (in Flag ==. 1) // need to carry it { 
                    { 

                        IF (the Integer.parseInt (str.charAt (I) + "") +. 1 == 2 ) 
                        {
                            str2 = "0" + str2;
                            flag = 1;
                        } else if (Integer.parseInt(str.charAt(i) + "") + 1 == 1)
                        {
                            str2 = "1" + str2;
                            index = i;
                            break;
                        }
                    }

                }
                str2 = str.substring(0, index) + str2;

            } else
            {
                str2 = str.substring(0, 7) + "1";
            }

            return str2;
        }
    }
}

 

 

2. pingbi principle variables of the same name

Output

 

 

3.

 byte (8), short (16), int (32), long (64) floating point: float (32), double (64)

A higher accuracy of the conversion to a lower precision data type without loss of accuracy, the loss of precision to a lower precision high precision data type conversion will

4

Float in the computer storage mechanism

 

 

5 string concatenation