Compiler theory quiz two jobs - grammar and language

1. grammar G (Z): Z-> aZb | ab definition of what kind of language?

    Z->aZb或Z->ab

  The aZb -> aaZbb or aZb -> aabb

  ~~~~~~~~~~~~~~~~

  Available so ....... A n- B n- 

  Therefore, G (Z): Z-> aZb | ab definition language is: L (G (the Z)) = {A n- B n- | n-> =. 1}

 

2. Write grammar quaternion form materials 22 pages identifiers in example 2.2.

  Grammar quad form:

  Grammar = G (V N , V T , P, S)

  V n- = {W is (identifier), Q (letters), K (number)}

  Vt={a,b,c,d...........z,0,1.......9}

  P={W-->Q | K }

  S={W}

 

3. Write the following expressions leftmost derivation and rightmost derivation syntax tree.

G (E):

E=> E + T | T

T=>T * F | F

F=>(E)| i

  • i*i+i
  • i+i*i
  • i+(i+i)

 Observe different leftmost and rightmost derivation process, as well as the similarities and differences of the syntax tree.

(1) the most left:

  E=>E+T=>E+F=>E+i=>T+i=>T*F+i=>T*i+i=>F*i+i=>i*i+i

  Rightmost derivation

  E=>E+T=>T+T=>T*F+T=>F*F+T=>i*F+T=>i*i+T=>i*i+F=>i*i+i

  Derivation Tree:

             

(2)

   Leftmost derivation:

  E=>E+T=>T+T=>F+T=>i+T=>i+T*F=>i+F*F=>i+i*F=>i+i*i

   Rightmost derivation

  E=>E+T=>E+T*F=>E+T*i=>E+F*i=>E+i*i=>T+i*i=>F+i*i=>i+i*i

   Derivation Tree:

              

(3)

   Leftmost derivation:

  E=>E+T=>T+T=>F+T=>i+T=>i+F=>I+(E)=>i+(E+T)=>i+(T+T)=>i+(F+T)=>i+(i+T)=>i+(i+F)=>i+(i+i)

   Rightmost derivation

  E=>E+T=>E+F=>E+(E)=>E+(E+T)=>E+(E+F)=>E+(E+i)=>E+(T+i)=>E+(F+i)=>E+(T+i)=>E+(i+i)=>T+(i+i)=>F+(i+i)=>i+(i+i)

   Derivation Tree:  

                 

Guess you like

Origin www.cnblogs.com/xiaoAP/p/11512369.html