Java static execution order

1. Definition:

　　1, Java static variables can only be defined in a class body, it can not be defined in the method. All belong to the class static variable not part of the method.

      2, static blocks: performing the JVM loads class with static stated, performed only once

　　      Building blocks: the class defined by {}, directly each time the object is created execution

             The priority order of execution: Static blocks> main ()> building block> Constructor

     3, load order the class

　　     (1) static objects and static parent class code block

　　     (2) static objects and static subclass code block

　　     (3) the parent non-static and non-static block objects

　　     (4) the parent class constructor

　　     (5) a subclass of non-static and non-static block objects

　　     (6) subclass constructor

 

   

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2, examples

 

public  class the Test {
     static  int AGE1 =. 1 ; 
 
    static { 
        AGE1 = 10 ; 
        System.out.println ( "this is a static block" ); 
    } 
 
    { 
        System.out.println ( "This is a normal block" + AGE1); 
    } 
 
    public the Test () { 
        System.out.println ( "this is the constructor" ); 
    } 
    
    public  void Fun () { 
        System.out.println ( "this is a common method of Fun" ); 
    } 
 
    public  static  void Show () { 
        System.out.println ("This is a static method" + AGE1); 
    } 
 
    public  static  void main (String [] args) { 
        System.err.println ( "==============" ); 
        
        Test.show ( ); 
        
        the Test T = new new the Test (); 
        t.fun (); 
        t.fun (); 
    } 
}

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3. Source:

   Static Java in order of execution: https://blog.csdn.net/u010859650/article/details/81587738

   java static code execution sequence:  https://www.cnblogs.com/sjxbg/p/8831346.html

  Java static order of execution: https://blog.csdn.net/ewzjs/article/details/78150198