When Java initialization code execution order

Java code execution order

To sum up: is static priority higher than the priority of non-static, static and non-static in the parent class is a subclass of higher priority than the priority.
The constructor can be attributed to non-static.
[No difference between static and static variables block fixed priority, who first defined, whoever performs]

1. Sample Code

public class TestInitialSeq extends Father {
  public static Print static_var_son = new Print("子类静态变量");

  public Print var_son = new Print("子类非静态变量");

  static {
    System.out.println("子类静态代码块");
  }

  {
    System.out.println("子类非静态代码块");
  }

  public TestInitialSeq() {
    System.out.println("子类构造函数");
  }

  public static void main(String[] args) {
    new TestInitialSeq();
  }
}

class Father {

  public Print var_father = new Print("父类非静态变量");

  static {
    System.out.println("父类静态代码块");
  }

  public static Print static_var_father = new Print("父类静态变量");

  {
    System.out.println("父类非静态代码块");
  }

  public Father() {
    System.out.println("父类构造函数");
  }
}

class Print {
  public Print(String word) {
    System.out.println(word);
  }
}

2. Sample results