The execution order of static code blocks, ordinary code blocks and construction methods

Let me talk about the conclusion first: static code block === > ordinary code block === > construction method
description: static code block will only be executed once when the class is loaded into memory, and the other two will be executed once every time new

public class Test{
    
    
    //静态代码快
    static {
    
    
        System.out.println("A");
    }

    //普通代码快
    {
    
    
        System.out.println("B");
    }

    //构造方法
    Test(){
    
    
        System.out.println("C");
    }


    public static void main(String[] args) {
    
    
        System.out.println("D");
        new Test();
        new Test();
    }
}

The output is:
A
D
B
C
B
C

++++++++++++++++++++++++++++++++++++ dividing line++++++++++++++ ++++++++++++++++++++++

If Test inherits a class at this time, does the echo load the subclass or the parent class?

class Person{
    
    
    Person(){
    
    
        System.out.println("E");
    }
}
public class Test{
    
    
    //静态代码快
    static {
    
    
        System.out.println("A");
    }

    //普通代码快
    {
    
    
        System.out.println("B");
    }

    //构造方法
    Test(){
    
    
        System.out.println("C");
    }


    public static void main(String[] args) {
    
    
        System.out.println("D");
        new Test();
        new Test();
    }
}

The output is:
A
D
E
B
C
E
B
C
So when the class is loaded, the parent class will be loaded first.