table of Contents
Set and logical operations
set
definition
We figurative and abstract things, symbols, called objects , a whole must be called by the objects that make up the collection , each composed of a collection of objects called elements .
In general, we do not contain any element of the set is called the empty set , denoted by \ (\ emptySet \) .
Containing a set of finite elements is called a finite set , comprising a set of elements called infinite infinite set .
nature
1. VARIATION : For a given set, which elements must vary.
2. Uncertainty : elements of the collection must be determined.
- For example, "China's municipalities," constitute a collection, "our small river" does not constitute a collection.
Common episodes
Nonnegative integers (natural numbers): \ (\ N \)
Positive integers: \ (\ N ^ * \) or \ (\ N _ + \)
Set of integers: \ (\ the Z-\)
Set of rational numbers: \ (\ Q \)
Real numbers: \ (\ R & lt \)
Show
We typically use a capital English letter \ (A, B, C, \ cdots \) represents a set, lowercase English letters \ (a, b, c, \ cdots \) represents an element in the collection.
If \ (A \) is the set \ (A \) element, say \ (A \) belonging to a set of \ (A \) , denoted \ (A \ in A \) ; Accordingly, if the if the \ (A \) B is not set \ (a \) element, say \ (a \) does not belong to the set of \ (a \) , denoted \ (a \ notin a \) .
Representation collection:
1. enumeration method : the elements enumerated, using "{}" enclose
EG. "Equation \ (x ^ 2 + x- 2 = 0 \) all real number of the" set enumeration method using a composition represented as \ (\ {1, -2 \} \) .
2. Description Method : In general, if the set \ (the I \) belonging to a set of \ (A \) of any one element \ (X \) has a characteristic \ (P (X) \) , not belonging to the set \ ( a \) no element having a characteristic \ (p (x) \) , called \ (p (x) \) is set \ (a \) characteristic properties. At this time, a set of \ (A \) may be described as \ (\ {x \ in I | p (x) \} \)
eg. disposed equation \ (x ^ 2 + x- 2 = 0 \) of the real roots \ (X \) , then the "equation \ (x ^ 2 + x- 2 = 0 \) all real roots" consisting of set \ (B \) represented by the described method was \ (\ {X \ in \ R & lt | X ^ 2 + X-2 = 0 \} \) , where \ (x ^ 2 + x- 2 = 0 \) is set \ (B \) characteristic properties.
The relationship between the set
Koshuwa Mako Collection
In general, for two sets \ (A, B \) , if the set \ (A \) of any one element is \ (B \) elements, said that the two sets have included relations, said the collection \ ( a \) is a set of \ (B \) of the subset , denoted by: \ (a \ B subseteq \) (or \ (B \ a supseteq \) ). Therefore, any one set \ (A \) are a subset of its own, i.e. \ (A \ A subseteq \) .
We require: the empty set is a subset of a set of arbitrary , that is, a collection for any \ (A \) , there \ (\ emptySet \ subseteq A \) .
If the set \ (A \) is a set of \ (B \) subset, and \ (B \) there is at least one element not belonging to \ (A \) , then the set \ (A \) is called a set of \ (B \ ) the subset , denoted by: \ (a \ B subsetneq \) or \ (B \ a supsetneq \) .
Using Venn map may be expressed as:
It can be inferred:
1. For the set \ (A, B, C \) , if the \ (A \ B subseteq, B \ subseteq C \) , then \ (A \ subseteq C \) .
2. For a set of \ (A, B, C \) , if the \ (A \ B subsetneq, B \ subsetneq C \) , then \ (A \ subsetneq C \) .
Power set
For a given set \ (A \) , set as a subset of all its elements called \ (A \) of the power set, denoted \ (P (A) \) .
If \ (| A | = n-\) , then \ (| P (A) | = 2 ^ {| A |} \) . (Where \ (| A | \) denote the set \ (A \) the number of elements, also known as a collection of \ (A \) potential)
Equal to the set
Generally, if the set \ (A \) for each element is set \ (B \) elements, and a set of \ (B \) for each element is set \ (A \) elements, then He said set \ (A \) equal to the set \ (B \) , denoted \ (A = B \) .
Available equivalent defined by: If \ (A \ B subseteq, B \ subseteq A \) , then the \ (A = B \) .
Collection operation
Intersection
Given by the set of two \ (A, B \) set of common elements constituting the set is called \ (A, B \) of intersection, referred to as \ (A \ CAP B \) .
FIG using Venn can be expressed as:
Defined by the intersection obtained, for any two sets \ (A, B \) , are:
\(A\cap B=B\cap A\)
\ (A \ cap A = A \)
\(A\cap \emptyset=\emptyset\cap A=\emptyset\)
If \ (A \ subseteq B, \ ) then \ (A \ cap B = A \)
Union
Given by the set of two \ (A, B \) the set of all elements constituting called \ (A, B \) and set, referred to as \ (A \ B Cup \) .
A Venn FIG be expressed as:
Defined by the union have, for any two sets \ (A, B \) , are:
\(A\cup B=B\cup A\)
\(A\cup A=A\)
\(A\cup \emptyset =\emptyset \cup A=A\)
If \ (A \ subseteq B, \ ) then \ (A \ cup B = B \)
Complement
In studying the relationship between the collection, a subset of the set if you want to study is a given set, this collection is called The Complete Works , usually \ (U \) represented.
Complete Works is relative.
For example, research number set, the set of real numbers constant \ (\ R & lt \) as the corpus; study when only a natural number, put the set of natural numbers \ (\ N \) as a corpus.
如果知道集合\(A\)是全集\(U\)的一个子集,由\(U\)中所有不属于\(A\)的元素组成的集合,叫做\(A\)在\(U\)中的(绝对)补集,记作:
\(\complement_UA\)(~\(A\))
用Venn图可表示为:
若给定集合\(A,B\),则\(A\)在\(B\)中的相对补集(差集)由属于\(B\)而不属于\(A\)的元素组成,记作\(B-A\)。
\(A\)在\(B\)中的差集其实就可以理解为\(A\cap B\)在\(B\)中的补集。
对称差
对于给定的集合\(A,B\),只属于其中一个集合,而不属于另一个集合的元素构成的集合叫做这个集合的对称差,记作:
\(A\Delta B\)(\(A\oplus B\))。
用Venn图可表示为:
集合运算在位运算中的表示
交集:A&B
并集:A|B
补集:~A
对称差:A^B
逻辑运算
逻辑连结词
在逻辑或数学中,我们常用逻辑词连结两个命题组成一个新命题,而常用的逻辑连结词有“且” “或” “非”。
且
若有命题\(p,q\),用"且"连结可组成一个新命题,记作\(p\wedge q\)。只有\(p,q\)都是真命题时,\(p\wedge q\)才是真命题。
或
若有命题\(p,q\),用"或"连结可组成一个新命题,记作\(p\vee q\)。只要\(p,q\)中有至少一个是真命题时,\(p\vee q\)就是真命题。
非
若有命题\(p\),对它加以否定则构成一个新命题,记作\(\neg p\)。\(p\)和\(\neg p\)的真假相反。
异或的表示:\(a \oplus b=(\neg a\wedge b)\vee (a\wedge \neg b)\)
优先级:非>与>异或>或
量词
对于含有变量的语句,当对它赋予一个值或条件时就可以成为一个命题。
全称量词
表示陈述事物全体的量词叫做全称量词,用符号\(\forall\)表示;含有全称量词的命题,叫做全称命题。
设\(p(x)\)是某集合\(M\)所有元素都含有的性质,则一个全称命题可记为:\(\forall x\in M,p(x).\)
存在量词
表示陈述事物个体或部分的量词叫做存在量词,用符号\(\exist\)表示;含有存在量词的命题,叫做存在性命题。
类似的,一个存在性命题可记为\(\exists x\in M,p(x).\)