pat (B)_1002

1002 Write this number (20 points)

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Reads a positive integer n, to calculate the sum of the digits, each digit and write Pinyin.

Input formats:

Each test comprises a test input, i.e. a natural number given value of n. Here guarantee n is less than . 1 0 . 1 0 0 power.

Output formats:

Output on a single line between each one, Pinyin number n of the sum of the digits 1 spaces, but after the last row Pinyin digital with no spaces.

Sample input: 1234567890987654321123456789

 

Sample output: yi san wu

 

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Code:

#include<stdio.h>

#include<string.h>

 

int main () {

    char num [101]; // n power of 10 up to 100, so creating an array 101 hold the input digital

    int a[10];

    int n = 0; // Number of request

    int t = 0; // sum bits

    int i;

    char m[][9] ={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};

    // string must be stored by the two-dimensional array, represents the number of rows, each column represents the maximum number of characters'

    gets (num); // use gets () function accepts characters from the keyboard, and then stored in array

    

    for(i=0;i<strlen(num);i++){

        n = n + num [i] -48; // determine the total number must be subtracted '0'.

    }

    while(n!=0){

        a[t]=n%10;

        n=n/10;

        t++;

    }

    printf("%s",m[a[t-1]]);

    for(i=t-2;i>=0;i--){

        printf(" %s",m[a[i]]);

    }

    return 0;

}