[LeetCode]Employees Earning More Than Their Managers

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than 
his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

This question is have a table Employee, the table contains the employee and their manager, respectively name columns, Salary column and ManagerId column, need to find a high salary employee collar than his manager's employee:

 Solution one:

select e1.Name as employee  from employee e1,employee e2
where e1.ManagerId = e2.Id and e1.Salary > e2.Salary;

Solution two:

select e1.Name as employee  from employee e1
join employee e2 on e1.ManagerId = e2.Id
where e1.Salary > e2.Salary;

Reproduced in: https: //www.cnblogs.com/lsyb-python/p/11074414.html