++ experiments

#include <stdio.h>  
int main()  
{  
    int a = 4;  
    printf("a=4\n");  
    printf("(a)*(++a)=%d\ta=%d\n",(a)*(++a),a);  
    a = 4;  
    printf("(++a)*(++a)=%d\ta=%d\n",(++a)*(++a),a);  
    a = 4;  
    printf("(a++)*(a++)=%d\ta=%d\n",(a++)*(a++),a);  
    a = 4;  
    printf("(a++)*(a)=%d\ta=%d\n",(a++)*(a),a);  
    scanf("%d",&a);  
} 

Disassembly:

Screenshot operating results:

The results show that, if an expression preincrement symbol exists, first increment operation are sequentially performed, then since the value calculated by the expression. For example, when a = 4 (a) * (++ a) is equal to 25 instead of 4 * 5 = 20. Post increment symbol Similarly, the first calculation expression with the value of the original value, the last increment sequentially performed operations.

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Reproduced in: https: //www.cnblogs.com/mashang/archive/2011/03/24/1993509.html