[Discrete Mathematics relationship and function

The basic concept 1, the relationship

Relationship is a subset of the Cartesian product -> relationship is set as an ordered pair of elements

 

Property 2, relationship

Let R be a relation on a set A, then:

nature

 

 

Relationship Matrix

relation chart

Reflexive

X belongs to any of A, XRX

I_A in R

Relationship matrix main diagonal elements are all 1

Diagram of all the points have loopback

Irreflexive

Any X, Y belonging to A, XRY => X! = Y

I_A∩R = sky

Relationship matrix main diagonal elements are all 0

Graph all the points are not self-loop

symmetry

Any X, Y belonging to A, XRY => YRX

R=R^T       

All the main diagonal relationship matrix symmetric positions on the same element value

There diagram A-> B must have B-> A

Antisymmetric

Any X, Y belonging to A, XRY && YRX => X = Y

R∩R ^ T belong to IA

All the elements of the matrix relationship symmetrically about the main diagonal position are not simultaneously 1

If diagram A-> B must not B-> A

Transitive

Any X, Y, Z belongs to A, XRY && YRZ => XRZ

R=R·R

slightly

slightly

Symmetric and antisymmetric

任意I,j,(I,j) = (j,i) = 0

Asymmetric not antisymmetric

任意<(I,j),(j,i)>取遍<0,0><0,1><1,0><1,1>

Does not reflexive anti-reflexive

With a major diagonal 1 0

 

3 operation, relations

Computing a set of inherited (cross and makeup etc.) has its own operation (inverse operation R ^ -1, complex arithmetic R · T, the closure operation)

 

Relations and operations (inherited from the collection)

Matrix representation

R∪S= MR ∨Ms    

Correspond directly to the position taken ∪

Complex arithmetic relations

Matrix representation

R◦S= MR ÙMS

A matrix multiplication, addition ∪ take place, the multiplication take ∩

Inverse operation relations

Matrix representation

R^-1=(MR)T

Relationship matrix inverse relationship is the relationship matrix transpose of the original relationship

 

4, special relations

Let R be a relation on A

Equivalence relation

&& && symmetric reflexive transitive

Determining a set of division

Quotient set A / R

A/R = { [a1]_R, [a2]_R,…}

Compatibility relation

&& && contains symmetrical reflexive transitive

Determine the coverage

Maximal Compatible Classes

Maximum complete polygon (n vertices FIG complete)

 

note:

 

A consistent relationship between the maximum compatibility class is not unique;

 

Vertices can be present in two compatible classes maximum inside (right)

Partial order

&& && antisymmetric reflexive transitive

 

Hasse

Hasse is a chain: total ordering relation ;

Each element of the A element has a minimum: well-ordered relationship ;

- each of the finite set of totally ordered set is well-ordered

Indeed bound upper bound lower bound on the lower boundary of what really is not a set of elements!

Coherent relationship

Antireflexive && && contains transmittable antisymmetric

 

 

 

| A | = N, then the binary relation on A has 2 ^ (N * N) species

Functional relationship

X is an arbitrary X, Y such that there is always belong y f (x) == y

Codomain X is called herein the domain of f, Y f is called, f is a subset of the range of Y ranf

Single-shot function

f(x1) == f(x2) => x1 == x2

| X | = m, | Y | = n, if m> = n, then there is the number of X to Y is a single shot: C (m, n) * m!

Surjective function

Ranf == Y, i.e. is equal range and codomain

| X | = m, | Y | = n, if m <= n, then there is the number of X to Y is Surjective: C (n, 0) * (n ^ m) - C (n, 1) * ( (n-1) ^ m) + ... + C (n, n-1) * (1 ^ m) (repulsive force receiving)

Injective function

Ranf a subset of Y

 

 

 

 

 

 

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Origin blog.csdn.net/sinat_39763590/article/details/86580282