题目描述
Given two strings a and b we define ab to be their concatenation. For example, if a = “abc” and b = “def” then ab = “abcdef”. If we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = “” (the empty string) and a^(n+1) = a*(a^n).
输入
Each test case is a line of input representing s, a string of printable characters. The length of s will be at least 1 and will not exceed 1 million characters. A line containing a period follows the last test case.
输出
For each s you should print the largest n such that s = a^n for some string a.
Sample input
ABCD
AAAA
ABABAB
.
Sample output
. 1
. 4
. 3
Given a string by the string A string composed of N, N seeking how much the maximum,
the use of an array next; L / (L-next [ L]) is also desired value
#include<bits/stdc++.h>
using namespace std;
char s[1000005];
int next[1000005];
void getnext(char *a)
{
int len=strlen(a);
int i=0,j=-1;
next[0]=-1;
while(i<len)
{
if(j==-1||a[i]==a[j])
next[++i]=++j;
else j=next[j];
}
}
int main()
{
while(scanf("%s",s)!=EOF&&s[0]!='.')
{
int len=strlen(s);
getnext(s);
if(len%(len-next[len])==0)
printf("%d\n",len/(len-next[len]));
else
printf("1\n");
}
return 0;
}