leetcode-easy-trees-101. Symmetric Tree-YES

mycode   92.44%

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def isSymmetric(self, root):
        """
        :type root: TreeNode
        :rtype: bool
        """
        def deal(root,level):
            if not root:
                self.res[level].append(None)
                return 0
            self.res[level].append(root.val)  
            deal(root.left,level+1)         
            deal(root.right,level+1)
            
        from collections import defaultdict
        self.res = defaultdict (List) # incoming int () function to initialize 
        Deal (root, 0)
         for Level, Item in self.res.items ():
             IF  not Item == Item [:: - 1 ]:
                 return False
         return True
        
       
            

 

reference

# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def isSymmetric(self, root):
        """
        :type root: TreeNode
        :rtype: bool
        """
        
        
        def traver(left,right):
            if not left and not right:
                return True
            if not left or not right:
                return False
            
            return (left.val == right.val) and traver(left.left,right.right) and traver(left.right,right.left)
        
        return traver(root,root)