topic
After downloading the zip, you can get the prompt text
Combining the question name and text prompts, it can be seen that it is the Caesar cipher
Use script to blast the number of bits of displacement
str1 = 'FRPHEVGL'
str2 = str1.lower()
num = 1
for i in range(26):
print("{:<2d}".format(num),end = ' ')
for j in str2:
if(ord(j)+num > ord('z')):
print(chr(ord(j)+num-26),end='')
else:
print(chr(ord(j)+num),end='')
num += 1
print('')
available
Only the 13th one is a word, so the key is 13, and then the plain text can be encrypted to obtain
Reference article link:
https://www.cnblogs.com/scarecr0w7/p/17377117.html