buu crypto power encryption

I. This binary powers of encryption somewhat different, can be determined from the size of the figures out of more than 4, and generally four or more already expressed within 31, and so is the clouds password to 0 as the delimiter, password 01248 composed of
two .Python code decryption

code="8842101220480224404014224202480122"
sum=0
flag=""
for i in code:
    if i!='0':
        sum+=int(i)
    else:
        print(sum)
        flag+=chr(sum+64)
        sum=0
flag+=chr(sum+64)
print(flag)