Array name and & array name

#include<stdio.h>
int main(){
    int arr[10] = {0};
    printf("%p\n",arr);
    printf("%p\n",&arr);
    return 0;
}

 

Although the results of the above code printout are the same, the meanings are different

 printf("%p\n",arr); This means that the address of the first element of the array is printed

printf("%p\n",&arr); This is to print the address of the array

 These two types are different

for example

#include<stdio.h>

int main (){
    int i = 97;
    char c = 'a';
    printf("%d\n",i);
    printf("%d\n",c);
    return 0;
}

 The values ​​printed by both are integers are the same, but their types are different

2.

int main(){
    int arr[10] = {0};
    int * p1 = arr;         //p1是一个整型指针
    int (*p2) [10] = &arr;  //p2是一个数组指针
    printf("%p\n",p1);
    printf("%p\n",p2);
    return 0 ;
}

Note the following code

int main(){
    int arr[10] = {0};
    int * p1 = arr;         //p1是一个整型指针
    int (*p2) [10] = &arr;  //p2是一个数组指针

    printf("%p\n",p1);
    printf("%p\n",p1+1); //这里指针+1 会跳过一个整型的指针（即跳过四个字节）
    printf("%p\n",p2);
    printf("%p\n",p2+1); //这里指针+1 会跳过一个整型数组的指针（即跳过40个字节）

    return 0 ;

}

 Output result:

 

 

When we take the address, &arr represents the address of the array, not the address of the first element of the array

    //练习
    double* d[5]; //d数组的每个元素 每个元素是double*类型的
    double*  (*pd)[5] = &d;
    //pd 就是一个数组指针
    //(*pd)[5] 这个说明 指针指向的是数组5个元素
    //double*  (*pd)[5] = &d;  这个说明 指针指向的是数组5个元素，指向的每个元素是double* 类型的

Replenish:

The array name is the address of the first element of the array

with two exceptions

1. sizeof(array name) - the array name represents the entire array, and the calculation is the size of the entire array, in bytes

2. &Array name- The array name indicates that the address of the entire array is retrieved from the entire array