Aidan Ward :
so i had a exam to day and while i found a way to make my code work i dont like it
public static void search(String name, Friend[] array) {
for (int i = 0; i<array.length;i++) {
if((array[i].getName()).equals(name)) {
System.out.println(name+ " is found at position " +i+"\n");
}
else {
System.out.print("\nName not in list\n");
}
}
}
So what i do here works, im searching the array of type Friend for a name ive passed from the main method. But i want to stop when it finds a unique name, so while i like what i have as it shows if there is more than one of the name i would like to show just the ones say that contain John and ignore every other name or if there is no John that it would just print a single "Name not in list"
Villat :
You can add a break
and also have a boolean
to avoid printing the same message over and over:
boolean nameFound = false;
for (int i = 0; i<array.length;i++) {
if((array[i].getName()).equals(name)) {
System.out.println(name+ " is found at position " +i+"\n");
nameFound = true;
break;
}
}
if(!nameFound) System.out.print("\nName not in list\n");
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