Table of contents
1.
# Implement a closure, implement mysum(1) = 1, mysum(2) = 3, mysum(3) = 6
def outer():
def mysum(arg):
if arg < 1:
print("数值错误")
elif arg < 2:
print(1)
elif arg < 3:
print(3)
elif arg < 4:
print(6)
elif arg >= 4:
print("数值错误")
return mysum
mysum = outer()
mysum(1)
mysum(2)
mysum(3)
'''
运行结果
1
3
6
'''2.
Use list comprehension to realize the list, (the elements in the list are, if it is an even number between 1-10, it is the cube of the even number, if it is an odd number, it is an odd number and take the remainder of three)
result = [i*i*i if i % 2 != 1 else i % 3 for i in range(1, 11)]
print(result)
"""
运算结果
# 1 2 3 4 5 6 7 8 9 10
# [1, 8, 0, 64, 2, 216, 1, 512, 0, 1000]
"""3.
# Use generator expression: generate 1-10 even numbers are unchanged, odd numbers are 0
def number(num):
for i in range(1, num + 1):
if i % 2 == 0:
yield i
else:
yield 0
mun = number(10)
for i in mun:
print(i)operation result
"""
0
2
0
4
0
6
0
8
0
10
"""