Determine whether each year in 2000-2500 is a leap year, and output the result.

Question: Determine whether each year in 2000-2500 is a leap year, and output the result.

Judgment conditions for leap year: (1): It is a leap year that is divisible by 4 but not divisible by 100.

                            (2): Divisible by 100 and 400 at the same time.

C language source program:

#include<stdio.h>
int main()
{
	int year;
	for(int i=2000;i<2500;i++)
	{
		year=i;
		
    if(year%4==0&&year%100!=0||year%400==0)
	{
		printf("%d 是闰年\n",year);	
	}
	else
	{
		printf("%d 不是闰年!\n",year);	
	} 
		
	}
	return 0;	
}