C++-Write a program to determine whether a certain year of keyboard input is a leap year.

• The conditions for a leap year are one of the following: ① Divisible by 4, but not divisible by 100, such as 2008 ② Divisible by 400, such as 2000
  mode one

#include <iostream>
using namespace std;
int main()
{
    
    
 int a;
 cout<<"请输入年份"<<endl;
 cin>>a;
 if(a%4==0&&a%100!=0||a%400==0)
    cout<<"闰年"<<endl;
 else
    cout<<"不是闰年"<<endl;
}

Way two

#include <iostream>
using namespace std;
int main()
{
    
    int y;
cin>>y;
if(y%4==0)
{
    
    
    if(y%100==0)
    {
    
    
    if(y%400==0)
    cout<<"IsLeapYear";
    else
    cout<<"NotLeapYear";
    }
    else cout<<"IsLeapYear";
    }
    else cout<<"NotLeapYear";
}