Clatty Cake :
Based on some sports results data, I have a Fixture
object which has getHome()
and getAway()
method. I'd like to shorten this method which I've written to only use a single lambda function (instead of creating a new list and two lambdas), is this possible?
private Collection<FixtureResult> finalResults(Team team) {
List<FixtureResult>finalResults = new ArrayList<>();
List<FixtureResult> homeResults = resultList.stream().filter(fixture ->
fixture.getHome().equals(team))
.collect(toList());
List<FixtureResult> awayResults = resultList.stream().filter(fixture ->
fixture.getAway().equals(team))
.collect(toList());
finalResults.addAll(homeResults);
finalResults.addAll(awayResults);
return finalResults;
}
user7 :
Simple enough
resultList.stream()
.filter(fixture -> fixture.getHome().equals(team) || fixture.getAway().equals(team)))
.collect(toList());
EDIT: This is on the assumption that order does not matter to you. If your final list needs to have home result and then away, have a look at Elliott Frisch's answer.
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