The following is a perpetual calendar program (single row) implemented in C language (for loop implementation):
Years in the normal int range will not be a problem
#include<stdio.h>
#include<Windows.h>
intmain()
{
int i,j,year,day1,mon[12]={31,28,31,30,31,30,31,31,30,31,30,31};
printf("Please enter the year: ");
scanf("%d",&year);
if(year%4==0&&year%100!=0||year%400==0)
{
mon[1]=29;
}
day1=(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;
for(j=0;j<12;j++)
{
printf("\n************************\n%d month\n day 123456\n",j+1);
for(i=0;i<day1;i++)
{
printf(" ");
}
for(i=1;i<=mon[j];i++)
{
printf("%3d",i);
if((i+day1-1)%7==6)
{
printf("\n");
}
}
day1=(day1+mon[d])%7;
}
system("pause");
}
Click the link below to view the n-row perpetual calendar
Click to open the n-row perpetual calendar