Shortest Proper PrefixHihoCoder - 1107
Query auto-completion(QAC) is widely used in many search applications. The basic idea is that when you type some string s in the search box several high-frequency queries which have s as a prefix are suggested. We say string s1 has string s2 as a prefix if and only if the first |s2| characters of s1 are the same as s2 where |s2| is the length of s2.
These days Little Hi has been working on a way to improve the QAC performance. He collected N high-frequency queries. We say a string s is a proper prefix if there are no more than 5 collected queries have s as a prefix. A string s is a shortest proper prefix if s is a proper prefix and all the prefixes of s(except for s itself) are not proper prefixes. Little Hi wants to know the number of shortest proper prefixes given N collected queries.
Hint: the 4 shortest proper prefixes for Sample Input are "ab", "bb", "bc" and "be". Empty string "" is not counted as a proper prefix even if N <= 5.
InputThe first line contains N(N <= 10000), the number of collected queries.
The following N lines each contain a query.
Each query contains only lowercase letters 'a'-'z'.
The total length of all queries are no more than 2000000.
Input may contain identical queries. Count them separately when you calculate the number of queries that have some string as a prefix.
OutputOutput the number of shortest proper prefixes.
12 a away abc abcde abcde abcba bcd bcde bcbbd bcac bee bbbSample Output
4
#include<iostream>
#include<cstdio>
#include<cstring>
#include<ctime>
#include<cstdlib>
#include<algorithm>
#include<cmath>
#include<string>
#include<queue>
#include<vector>
#include<stack>
#include<list>
using namespace std;
const int maxn=10000000+10;
int trie[maxn][30];
int f[maxn];
int cnt;
int ans;
void _insert(char *b)
{
int temp=0;
int len=strlen(b);
for(int i=0;i<len;i++)
{
f[temp]++;
if(!trie[temp][b[i]-'a']) trie[temp][b[i]-'a']=++cnt;
temp=trie[temp][b[i]-'a'];
}
f[temp]++;
}
void dfs(int u)
{
if(u==0) return ;
if(f[u]>0&&f[u]<=5) {ans++;return ;}
for(int i=0;i<26;i++)
{
if(trie[u][i]>0)
dfs(trie[u][i]);
}
}
int main()
{
int n;
char a[12];
scanf("%d",&n);
while(n--)
{
scanf("%s",a);
_insert(a);
}
for(int i=0;i<26;i++)
{
dfs(trie[0][i]);
}
printf("%d\n",ans);
}