HDU 4911 Inversion

HDU 4911 Inversion

merge sort

Find the number of inverse pairs

AC code

#include<iostream>
#include<cstdio>

#include<cstring>
#include<bitset>
#include<sstream>
#include<string.h>
#include<iomanip>

#include<cmath>
#include<algorithm>
#include<cstdlib>

#include<set>
#include<map>
#include<queue>
#include<vector>
using namespace std;
#define ll long long 
const ll inf=0x3f3f3f3f;
typedef pair<int ,int > PII;
const int maxn=1e5+10;
ll a[maxn],b[maxn],cnt;
void merge(ll l,ll mid ,ll r){
    
    
	ll i=l,j=mid+1,t=0;
	while(i<=mid&j<=r){
    
    
		if(a[i]>a[j]){
    
    
			b[t++]=a[j++];
			cnt+=mid-i+1;
		}else{
    
    
			b[t++]=a[i++];
		}
	}
	while(i<=mid)b[t++]=a[i++];
	while(j<=r)b[t++]=a[j++];
	for(i= 0; i<t;i++)a[l+i]=b[i];
}
void mergesort(ll l ,ll r){
    
    
	if(l<r){
    
    
		ll mid=(l+r)/2;
		mergesort(l,mid);
		mergesort(mid+1,r);
		merge(l,mid,r);
	}
}
int main(){
    
    
	#define io
	#ifdef io
		freopen("in.txt","r",stdin);
	#endif
	ll n,k;
	while(~scanf("%lld%lld",&n,&k)){
    
    
	cnt=0;
	for(ll i=0;i<n;i++)scanf("%lld",&a[i]);
		mergesort(0,n-1);
		if(cnt<=k)cout<<0<<endl;
		else printf("%lld\n",cnt-k);	
	}
	return 0;
}

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