Gives a permutation 0 ~ n-1 can be moved integrally, seeking to reverse the minimum
The numbers added num [i] is equivalent to tree-like array of n-num [i] plus 1 bit
Because the num [i] is the first (n-1) -num [i] + 1 = n-num [i] large number, generating reverse order, only the numbers may have been inserted prior to, this time interval query directly i.e. can
1 #include <set> 2 #include <map> 3 #include <cmath> 4 #include <queue> 5 #include <vector> 6 #include <cstdio> 7 #include <cstdlib> 8 #include <cstring> 9 #include <iostream> 10 #include <algorithm> 11 using namespace std; 12 const int MAXN=5001; 13 int a[MAXN],n,t=1,T; 14 int lb(int i){return i&-i;} 15 void init(){memset(a,0,sizeof(a));} 16 void add(int i,int v){for(;i<=n;a[i]+=v,i+=lb(i));} 17 int sum(int i){int ans=0;for(;i;ans+=a[i],i-=lb(i));return ans;} 18 int query(int i,int j){return sum(j)-sum(i-1);} 19 20 int num[MAXN],cnt,ans; 21 int main() { 22 while(scanf("%d",&n)!=EOF){ 23 init(),cnt=0; 24 for(int i=1;i<=n;i++)scanf("%d",&num[i]); 25 for(int i=1;i<=n;i++)cnt+=query(1,n-num[i]-1),add(n-num[i],1); 26 ans=cnt; 27 for(int i=1;i<n;i++){ 28 add(n-num[i],-1); 29 cnt+=query(1,n-num[i]-1)-num[i]; 30 add(n-num[i],1); 31 ans=min(ans,cnt); 32 } 33 cout<<ans<<endl; 34 } 35 return 0; 36 }