[Single chip notes] practical circuit for op amp current detection

1. Low-end op amp current detection method:


Analyze the principle:

Using the virtual short characteristics of the op amp , we get:

V + = V-

Using the virtual-off characteristic of the op amp , there is no current flowing through the input and output. So the currents flowing through R3 and R6 are equal .

(VOUT-V-)/R3 = V-/R6

From the above two equations, we can get

VOUT = V+ * (R3 + R6)/R6

And there is:

V +  = I * R 8

So have:

I =V+ / R8 = VOUT * R6/(R3 + R6)/R8

The current is converted in this way, the resistance of several resistors is adjusted, and V out can be sampled by the ADC of the microcontroller.


2. High-end current detection circuit


The ultimate purpose of this circuit to detect the current is to obtain the relationship between V OUT and V 1 and V 2 on the figure .

Let's analyze the input first, the virtual break can be seen:

V + /R 7  = (V 2 -V + ) / R 5

Imaginary short gets:

V + = V-

The current of one path of the input negative is equal:

(V--VOUT)/R1 = (V1-V-)/R2

Usually when using this circuit there are R 1  = R 7 , R 2  = R 5 .

The above formula includes:

VOUT = (V2-V1)*R1/R2

V2-V1 = I*R4;

so 

I = VOUT*R2/(R1*R4) ;

The above is to record and share the content.

By Urien February 26, 2018 11:00:07


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