Pandas bug notes (continuously updated)

Update to 2018.5.1

Dictionary to generate DataFrame

Today a dictionary generates a DataFrame in the following form, each value is a number (not a vector)

df = pd.DataFrame({
    'id': data_speed.index,
    'Mileage':data_speed['count']*data_speed['mean'],
    'SpeedAve':data_speed['mean'],
    'SpeedStd':data_speed['std'],
    'SpeedMax':data_speed['max'],
    'HeightAve':data_height['mean'],
    'HeightStd':data_height['std'],
    })

The result broke the following error

ValueError: If using all scalar values, you must pass an index

It turns out that you can use a dictionary to generate a DataFrame, {'A':[ 'a'], 'B': ['b']}but of course it doesn't have to be like this, so three methods can be successful: Quote
from: Statistician's Python Diary: Supplement on the Fourth Day The
first: {'A ':['a'], 'B': ['b']}

>>> df = pd.DataFrame({'A': ['a'], 'B': ['b']})
>>> df
   A  B
0  a  b

The second: pass in the index index

>>> df = pd.DataFrame({'A': 'a', 'B': 'b'}, index=[0])
>>> df
   A  B
0  a  b

The third type: DataFrame([dict])

>>> df = pd.DataFrame([{'A': 'a', 'B': 'b'}])
>>> df
   A  B
0  a  b