A. A Variety of Operations

只能说水题  ,看懂题目规则就行了

#include "bits/stdc++.h"
 
using namespace std;
int t;
int a,b;
int main()
{
    cin >> t;
    while (t--) {
        cin >> a >> b;
        //  题目给你2个0 能不能改成他给的俩个数,
         2个数为一奇一偶肯定 不能成功直接-1,
        否则俩个相同并且不为0 答案就是1,不然答案为2 
        if ((a + b) & 1) cout << -1 << endl;
        else {
            if (a + b == 0) cout << 0 << endl;
            else if (a == b)cout << 1 << endl;
            else cout << 2 << endl;
        }
    }
    return 0;
}

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Origin blog.csdn.net/weixin_53013914/article/details/120021004