过滤两个数组并取出不同/相同项(vue/filter)

话不多说 直接上干货内联代码片

// 数组A
let arrA = ['1111','2222','333','4444','5555']
// 数组B
let arrB= ['aaa','bbb','4444','5555','dddd','eeee','ffff','yyyy','mmmm']
过滤B数组中不包含A数组的项
let differentArr = arrB.filter(item => arrA.indexOf(item.id) > -1)
// differentArr =['aaa','bbb','dddd','eeee','ffff','yyyy','mmmm']
过滤B数组中包含A数组的项
let differentArr = arrB.filter(item => arrA.indexOf(item.id) != -1)
// differentArr =['4444','5555']

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Origin blog.csdn.net/miem_yang/article/details/118363671