Scientific notation is a convenient method used by scientists to represent very large or very small numbers. It satisfies the regular expression [+-][1-9] .[0-9]+E[+-][0- 9]+, that is, the integer part of the number has only 1 digit, and the decimal part has at least 1 digit. The sign of the number and its exponent part must be clearly given even for positive numbers.
Now the real number A is given in the format of scientific notation. Please write a program to output A according to the ordinary number representation, and ensure that all valid digits are reserved.
Input format:
Each input contains 1 test case, which is a real number A expressed in scientific notation. The storage length of this number does not exceed 9999 bytes, and the absolute value of its exponent does not exceed 9999.
Output format:
For each test case, output A in a line according to ordinary number notation, and ensure that all valid bits are reserved, including the 0 at the end.
Input example 1:
+1.23400E-03
Output sample 1:
0.00123400
Input example 2:
-1.2E+10
Output sample 2:
-12000000000
#include<stdio.h>
#include<iostream>
using namespace std;
int main() {
string s;
int k,kk;
while(getline(cin,s)) {
int e=0,t;
string shu="";
if(s[0]=='+')k=1;
else k=-1;
for(int i=1; i<s.size(); i++) {
if(s[i]=='E') {
t=i;
break;
} else if(s[i]=='.'){
continue;
}else {
shu+=s[i];
}
}
if(s[t+1]=='+')kk=1;
else kk=-1;
for(int i=t+2; i<s.size(); i++) {
e=e*10+s[i]-48;
}
//t-3就是点到e中有几个
if(k==-1){
cout<<"-";
}
if(kk==1){
if(t-3<e){
cout<<shu;
e=e-t+3;
while(e--){
cout<<"0";
}
}else if(t-3==e){
cout<<shu;
}
else{
for(int i=0;i<=e;i++){cout<<shu[i];}
cout<<".";
for(int i=e+1;i<shu.size();i++){cout<<shu[i];}
}
cout<<endl;
}
else if(kk==-1){
cout<<"0"<<".";
e=e-1;
while(e--){
cout<<"0";
}
for(int i=0;i<shu.size();i++){cout<<shu[i];}
cout<<endl;
}
}
}