Test point analysis
- Test points 2, 3, and 4 are all judging the situation where 0 is placed behind (the question is still quite tricky)
- The example of test point 4 judgment is +1.234564E+2 output should be 123.4564
- The example of the judgment of test points 2 and 3 is +1.23E+2 and the output should be 123
attach code
#include<iostream>
#include<algorithm>
#include<vector>
#include<cstring>
#include<cmath>
using namespace std;
int main(){
string str;
string strNumber="";
int numE,i,number;
char type;
int count;
int temp,t;
cin>>str;
if(str[0]=='-'){//正负
cout<<str[0];
}
numE=str.find('E');
type=str[numE+1];
strNumber=str.substr(numE+2,str.length()-1);//截取字符串
count=0;
temp=1;
for(i=strNumber.length()-1;i>=0;i--){//截取字符串转为int
count+=(strNumber[i]-'0')*temp;
temp*=10;
}
if(type=='+'){//0放后面
cout<<str[1];
for(i=3,t=0;i<numE;i++,t++){
cout<<str[i];
if(t==count-1&&i!=numE-1){//小数点后还有数字
cout<<'.';
}
}
for(i=0;i<count-(numE-3);i++){
cout<<0;
}
cout<<endl;
}
else{//0放前面
for(i=0;i<count;i++){
cout<<0;
if(i==0){
cout<<'.';
}
}
cout<<str[1];
for(i=3;i<numE;i++){
cout<<str[i];
}
cout<<endl;
}
return 0;
}