Idea: There are two difficulties in this question:
1. To find the time difference, use the formula ((end time at return-start time at return) + (end time at arrival-start time at arrival)) / 2
2. Input data Too complicated, because there is (+x) behind, the format of reading may be different, so you cannot use scanf to read, first use getline to read the data, and then add (+x) to the data without (+x) , And then use sscanf to read, c_str() will be used to return the address. For details, see the use of sscanf and the use of c_str() in the related blog
Code:
# include<iostream>
# include<cstdio>
# include<cstring>
# include<algorithm>
using namespace std;
int get_secend(int h,int m,int s)
{
return h * 3600 + m * 60 + s;
}
int get_time()
{
string line;
getline(cin,line);
if(line.back() != ')')
{
line += " (+0)";
}
int h1,m1,s1,h2,m2,s2,d;
sscanf(line.c_str(),"%d:%d:%d %d:%d:%d (+%d)",&h1,&m1,&s1,&h2,&m2,&s2,&d);
return get_secend(h2,m2,s2) - get_secend(h1,m1,s1) + d * 3600 * 24;
}
int main()
{
int t;
cin >> t;
string line;
getline(cin,line);//忽略掉第一行的回车
while(t--)
{
int time = (get_time() + get_time()) / 2;
int hour = time / 3600;
int minute = time % 3600 / 60;
int secends = time % 60;
printf("%02d:%02d:%02d\n",hour,minute,secends);
}
return 0;
}